# Complete IB Diploma (IBDP HL & SL) Study Guide: Biology, Chemistry, Physics, Economics, Business & TOK

> Score a 7 in your IB Diploma (IBDP Higher Level & Standard Level) exams with 192 active-recall flashcards covering IB Biology, IB Chemistry, IB Physics, IB Economics, Business Management, and Theory of Knowledge (TOK).

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- **Topic / Curriculum:** IB Diploma Programme (IBDP HL & SL): Biology, Chemistry, Physics, Economics, Business & TOK
- **Language:** en

# Complete IB Diploma (IBDP HL & SL) Study Guide: Biology, Chemistry, Physics, Economics, Business & TOK

Score a 7 in your IB Diploma (IBDP Higher Level & Standard Level) exams with 192 active-recall flashcards covering IB Biology, IB Chemistry, IB Physics, IB Economics, Business Management, and Theory of Knowledge (TOK).

> **[Explore All Interactive Flashcard Decks for This Exam Curriculum on Flashcards.world →](https://flashcards.world/flashcards/?q=IB%20Diploma%20Programme%20%28IBDP%20HL%20%26%20SL%29%3A%20Biology%2C%20Chemistry%2C%20Physics%2C%20Economics%2C%20Business%20%26%20TOK&back_lng=en)**

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## 1. Complete 6-Deck Progressive Curriculum Matrix (192 Flashcards)

| Module | Level | Curated Flashcard Deck | Cards | Practice Link |
| :--- | :--- | :--- | :--- | :--- |
| **Module 1** | `basic` | **[IB Biology HL/SL: Unity & Diversity, Molecular Biology, Cell Respiration, Photosynthesis & Genetics](/flashcards/sets/25cbaf04-d7cc-4bbd-a891-bda3cff283ab/)** | 32 | [Study Deck →](https://flashcards.world/flashcards/sets/25cbaf04-d7cc-4bbd-a891-bda3cff283ab/) |
| **Module 2** | `basic` | **[IB Chemistry HL/SL: Stoichiometry, Atomic Structure, Periodicity, Chemical Bonding (VSEPR) & Energetics](/flashcards/sets/dbfc2c76-07ca-4b0e-aef5-fcd119e44d59/)** | 32 | [Study Deck →](https://flashcards.world/flashcards/sets/dbfc2c76-07ca-4b0e-aef5-fcd119e44d59/) |
| **Module 3** | `intermediate` | **[IB Biology & Chemistry HL: Human Physiology, Neurobiology, Chemical Kinetics, Acids/Bases, Redox & Organic Pathways](/flashcards/sets/13b688fc-4d5c-4811-ac07-2f6706cb6583/)** | 32 | [Study Deck →](https://flashcards.world/flashcards/sets/13b688fc-4d5c-4811-ac07-2f6706cb6583/) |
| **Module 4** | `intermediate` | **[IB Physics HL/SL: Space, Time & Motion, Particulate Nature of Matter, Wave Behaviour, Fields & Nuclear/Quantum Physics](/flashcards/sets/19d8f607-55a8-4745-aedb-07a1fe674596/)** | 32 | [Study Deck →](https://flashcards.world/flashcards/sets/19d8f607-55a8-4745-aedb-07a1fe674596/) |
| **Module 5** | `advanced` | **[IB Economics & Business Management HL/SL: Elasticities, Market Failure, Macroeconomics, International Trade & Financial Ratios](/flashcards/sets/b8ab1326-d713-43b5-a72e-e8b1bf5a3d4a/)** | 32 | [Study Deck →](https://flashcards.world/flashcards/sets/b8ab1326-d713-43b5-a72e-e8b1bf5a3d4a/) |
| **Module 6** | `advanced` | **[IB Psychology, History & Theory of Knowledge (TOK): Biological/Cognitive/Sociocultural Approaches, Authoritarian States & TOK Exhibition/Essay](/flashcards/sets/7ec3c58b-9f16-49e9-ae0c-68f2e0a14171/)** | 32 | [Study Deck →](https://flashcards.world/flashcards/sets/7ec3c58b-9f16-49e9-ae0c-68f2e0a14171/) |

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## 2. Module-by-Module Syllabus, Quick-Reference Tables & Sample Flashcards

### Module 1 (BASIC): [IB Biology HL/SL: Unity & Diversity, Molecular Biology, Cell Respiration, Photosynthesis & Genetics](/flashcards/sets/25cbaf04-d7cc-4bbd-a891-bda3cff283ab/)

**Module Scope & Exam Blueprint**: IBDP Biology (SL & HL) core revision covering Theme A–D: endosymbiotic theory, water & carbon macromolecules, enzyme kinetics, Davson-Danielli vs Singer-Nicolson membrane models, DNA replication, gene expression, cell respiration, photosynthesis, and inheritance.

- **Direct Deck Link**: [IB Biology HL/SL: Unity & Diversity, Molecular Biology, Cell Respiration, Photosynthesis & Genetics (32 Cards)](https://flashcards.world/flashcards/sets/25cbaf04-d7cc-4bbd-a891-bda3cff283ab/)
- **Browse Level Sets**: [BASIC Flashcard Sets on Flashcards.world](https://flashcards.world/flashcards/?q=IB%20Diploma%20Programme%20%28IBDP%20HL%20%26%20SL%29%3A%20Biology%2C%20Chemistry%2C%20Physics%2C%20Economics%2C%20Business%20%26%20TOK&back_lng=en&expertise_level=basic)

| High-Yield Exam Concept / Question | Verified Answer & Core Rule |
| :--- | :--- |
| **Describe the roles of all 7 enzymes/proteins in HL prokaryotic DNA replication (Helicase, Gyrase, Primase, DNA Pol III, DNA Pol I, Ligase, SSBs).** | 1) DNA Gyrase (topoisomerase): relieves torsional strain ahead of replication fork; 2) DNA Helicase: unwinds double helix by breaking H-bonds; 3) Single-Stranded Binding proteins (SSBs): prevent strands re-annealing; 4) RNA Primase: synthesises short RNA primer; 5) DNA Polymerase III: synthesises new DNA strand 5'→3' (continuous on leading strand, discontinuous Okazaki fragments on lagging strand) using dNTPs; 6) DNA Polymerase I: removes RNA primers and replaces them with DNA; 7) DNA Ligase: seals nicks by forming covalent phosphodiester bonds. |
| **Explain the structure and function of Nucleosomes in eukaryotic chromatin packaging and gene expression regulation (HL).** | A nucleosome consists of DNA (~147 base pairs) wrapped nearly twice around an octamer core of 8 positively charged histone proteins (2 each of H2A, H2B, H3, H4), secured by an H1 linker histone. Nucleosomes supercoil DNA to fit inside the nucleus, protect DNA from damage, and regulate transcription via acetylation/methylation of histone tails (euchromatin = loosely packed, active transcription; heterochromatin = tightly condensed, silent). |
| **How does eukaryotic post-transcriptional modification of pre-mRNA (5' capping, 3' polyadenylation, and alternative splicing) work (HL)?** | 1) A methylated guanine (7-methylguanosine) cap is added to the 5' end and a poly-A tail (100–250 adenine nucleotides) is added to the 3' end to protect mRNA from exonuclease degradation and aid nuclear export/ribosome binding; 2) Spliceosomes remove non-coding introns and join exons; 3) Alternative splicing splices different combinations of exons from the same gene, enabling one gene to code for multiple distinct polypeptide isoforms. |
| **Compare Competitive vs Non-Competitive Enzyme Inhibition using Michaelis–Menten curves (Km and Vmax) and explain End-Product Inhibition (HL C1.1).** | Km (Michaelis constant) is the substrate concentration at ½ Vmax (inverse measure of enzyme affinity for substrate). Competitive inhibition: increases Km (lowers apparent affinity) while Vmax remains unchanged at high [S]. Non-competitive (allosteric) inhibition: decreases Vmax while Km remains unchanged. End-product inhibition: the final product of a metabolic pathway binds to an allosteric site on the first enzyme in the pathway (e.g., isoleucine inhibiting threonine deaminase), providing negative feedback. |
| **Contrast the structure and function of the mitochondrial compartments in HL Aerobic Cell Respiration (C1.2).** | 1) Outer membrane: smooth, contains transport proteins (porins) permeable to pyruvate. 2) Intermembrane space: tiny volume so pumped H⁺ protons rapidly build up a steep proton motive force (electrochemical gradient). 3) Inner membrane: folded into cristae (huge surface area) containing electron transport chain complexes and ATP synthase. 4) Matrix: fluid containing enzymes and optimal pH for the Link Reaction and Krebs Cycle, plus 70S ribosomes and circular mitochondrial DNA. |
| **Detail the HL stages of Aerobic Cell Respiration: Glycolysis, Link Reaction, Krebs Cycle, and Chemiosmosis / Oxidative Phosphorylation.** | Glycolysis (cytoplasm): Glucose (6C) + 2 ATP → 2 TP (3C) → oxidised (2 NAD⁺ → 2 NADH) + 4 ATP → 2 Pyruvate (net 2 ATP, 2 NADH). Link Reaction (matrix): Pyruvate + CoA + NAD⁺ → Acetyl-CoA (2C) + CO2 + NADH. Krebs Cycle (matrix): Acetyl-CoA (2C) + Oxaloacetate (4C) → Citrate (6C) → 5C → 4C (per Acetyl-CoA: 2 CO2, 3 NADH, 1 FADH2, 1 ATP). Oxidative Phosphorylation (cristae): NADH and FADH2 donate electrons to ETC, pumping H⁺ into intermembrane space; H⁺ flows through ATP synthase to phosphorylate ADP; O2 is terminal electron acceptor forming H2O. |
| **What is the difference between an Action Spectrum and an Absorption Spectrum in photosynthesis, and how do you calculate Rf in TLC of leaf pigments (C1.3)?** | An Absorption Spectrum plots the percentage of light absorbed by each photosynthetic pigment (chlorophyll a, chlorophyll b, carotenoids) against wavelength (peaks in blue ~450 nm and red ~670 nm; green ~500–550 nm reflected). An Action Spectrum plots the overall rate of photosynthesis at each wavelength of light. In Thin-Layer Chromatography (TLC): Rf = (distance travelled by pigment spot) ÷ (distance travelled by solvent front). |
| **Compare Cyclic and Non-Cyclic Photophosphorylation in the Light-Dependent Reactions of HL Photosynthesis.** | Non-cyclic photophosphorylation involves both Photosystem II (P680) and Photosystem I (P700): photolysis of water replaces electrons at PSII (producing O2), plastoquinone/cytochrome b6f pumps H⁺ into the thylakoid space to make ATP via chemiosmosis, and ferredoxin + NADP reductase reduce NADP⁺ to NADPH at PSI. Cyclic photophosphorylation (when NADP⁺ runs low) recycles excited electrons from PSI back to the cytochrome proton pump, producing additional ATP for the Calvin Cycle but NO NADPH and NO O2. |

| # | Front (Active Recall Prompt) | Back (Verified Exam Explanation) |
| :--- | :--- | :--- |
| **1** | What three pieces of evidence support the Endosymbiotic Theory for the origin of eukaryotic mitochondria and chloroplasts (IB Biology A2.2)? | Mitochondria and chloroplasts evolved from engulfed independent prokaryotes: 1) Both possess their own single circular naked DNA molecule (like bacteria); 2) Both contain 70S ribosomes (smaller than eukaryotic 80S cytoplasmic ribosomes); 3) Both have a double membrane (inner membrane from prokaryote, outer from host food vacuole) and divide independently by binary fission. |
| **2** | State the seven functions of life (MR H GREN / MR SHENG) demonstrated by unicellular organisms such as Paramecium and Chlorella. | Metabolism (enzyme-catalysed reactions in cytoplasm), Response (reacting to stimuli, e.g., cilia in Paramecium or eyespot in Chlamydomonas), Homeostasis (contractile vacuoles expelling excess water), Growth (increase in cell size/biomass), Reproduction (asexual mitosis or sexual), Excretion (diffusion of metabolic waste across plasma membrane), and Nutrition (heterotrophic endocytosis in Paramecium vs autotrophic photosynthesis in Chlorella). |
| **3** | Why does the surface area-to-volume ratio (SA:V) limit maximum cell size, and how do cells adapt to high metabolic rates? | As a cell's radius r increases, volume increases cubically (∝ r³), determining the rate of metabolism/heat/waste production, whereas surface area increases quadratically (∝ r²), determining the rate of exchange across the membrane. Thus SA:V decreases as cells grow larger; cells with high metabolic rates adapt via microvilli, flattened shapes (erythrocytes), or invaginations (cristae/thylakoids). |
| **4** | How did falsification of the Davson–Danielli (sandwich) model lead to the Singer–Nicolson Fluid Mosaic Model of membranes (IB Biology B2.1)? | Davson–Danielli proposed a phospholipid bilayer coated on both sides by continuous layers of hydrophilic globular proteins. It was falsified by: 1) Freeze-etched electron micrographs showing transmembrane globular proteins embedded inside the core of the bilayer; 2) Fluorescent antibody tagging (Frye & Edidin) showing membrane proteins drift laterally; 3) Amphipathic structure of isolated membrane proteins. |
| **5** | Compare how hydrophilic (polar/charged) and hydrophobic (non-polar) substances are transported in blood plasma. | Sodium chloride (NaCl) and amino acids are ionic/zwitterionic and dissolve directly in water. Glucose is polar and freely water-soluble. Oxygen (O2) is non-polar with low solubility in water, so it is bound to haemoglobin inside erythrocytes. Cholesterol and triglycerides (fats) are hydrophobic/non-polar and are transported inside lipoprotein complexes (monolayer of amphipathic phospholipids + proteins surrounding a hydrophobic core). |
| **6** | How do Hershey and Chase's (1952) T2 bacteriophage experiment and Rosalind Franklin's X-ray diffraction support DNA structure and function (A1.2)? | Hershey & Chase labelled phage protein coats with radioactive sulfur (³⁵S) and phage DNA with radioactive phosphorus (³²P). After infection and centrifugation, ³²P was found inside the bacterial pellet while ³⁵S remained in the liquid supernatant, proving DNA (not protein) is the genetic material. Franklin's Photo 51 X-ray diffraction pattern showed a cross-shaped pattern proving a helical structure with regular 3.4 nm pitch and hydrophobic bases stacked inside. |

### Module 2 (BASIC): [IB Chemistry HL/SL: Stoichiometry, Atomic Structure, Periodicity, Chemical Bonding (VSEPR) & Energetics](/flashcards/sets/dbfc2c76-07ca-4b0e-aef5-fcd119e44d59/)

**Module Scope & Exam Blueprint**: IBDP Chemistry (Structure 1–3 & Reactivity 1) core and HL revision: mole concept & gas laws, emission spectra & ionisation energies, VSEPR electron domain geometries, hybridisation (sp/sp2/sp3), Period 3 oxides, transition metal complexes, Born-Haber cycles, and entropy/Gibbs free energy.

- **Direct Deck Link**: [IB Chemistry HL/SL: Stoichiometry, Atomic Structure, Periodicity, Chemical Bonding (VSEPR) & Energetics (32 Cards)](https://flashcards.world/flashcards/sets/dbfc2c76-07ca-4b0e-aef5-fcd119e44d59/)
- **Browse Level Sets**: [BASIC Flashcard Sets on Flashcards.world](https://flashcards.world/flashcards/?q=IB%20Diploma%20Programme%20%28IBDP%20HL%20%26%20SL%29%3A%20Biology%2C%20Chemistry%2C%20Physics%2C%20Economics%2C%20Business%20%26%20TOK&back_lng=en&expertise_level=basic)

| High-Yield Exam Concept / Question | Verified Answer & Core Rule |
| :--- | :--- |
| **Explain Formal Charge (FC), Resonance Structures, Delocalisation, and Bond Order in O3, CO3²⁻, NO3⁻, and Benzene (HL Structure 2.2).** | Formal Charge: FC = (Valence electrons in free atom) − ½(Bonding electrons) − (Non-bonding lone pair electrons). The most stable Lewis structure has FC values closest to zero and any negative FC on the most electronegative atom. Resonance hybrids occur when π-electrons delocalise over >2 atoms: Ozone (O3) has 2 resonance structures (bond order = 1.5, intermediate length/strength); Carbonate (CO3²⁻) and Nitrate (NO3⁻) have 3 resonance structures (bond order = 1.33); Benzene has bond order = 1.5. |
| **Explain how Ozone (O3) is continuously formed and depleted in the stratosphere (Chapman Cycle), why O3 absorbs longer-wavelength UV than O2, and how CFCs/NOx catalyse ozone depletion.** | O2 has a double bond (bond order 2, BE = 498 kJ mol⁻¹), requiring high-energy short-wavelength UV-C (< 242 nm) to dissociate, whereas O3 has weaker delocalised bonds (bond order 1.5, BE = 364 kJ mol⁻¹), so it is dissociated by longer-wavelength, lower-energy UV-B (< 330 nm). CFCs (e.g., CF2Cl2) undergo C–Cl homolytic fission in UV light to release chlorine free radicals (Cl•): Cl• + O3 → ClO• + O2, then ClO• + O• → Cl• + O2 (net: O3 + O• → 2O2, regenerating Cl• to destroy thousands of O3 molecules). |
| **Distinguish between Sigma (σ) and Pi (π) covalent bonds, and determine the Hybridisation (sp³, sp², sp) of carbon/nitrogen/oxygen atoms (HL Structure 2.2).** | Sigma (σ) bond: formed by head-on axial overlap of atomic/hybrid orbitals, concentrating electron density along the internuclear axis (all single bonds are σ bonds). Pi (π) bond: formed by sideways parallel overlap of unhybridised p-orbitals above and below the internuclear axis (a double bond = 1σ + 1π; a triple bond = 1σ + 2π). Hybridisation matches the number of electron domains around the atom: 4 domains = sp³ (109.5°); 3 domains = sp² (120°); 2 domains = sp (180°). |
| **Compare the structures, bonding, and physical properties of the four covalent allotropes of Carbon: Diamond, Graphite, Graphene, and Buckminsterfullerene (C60).** | 1) Diamond: giant covalent network, sp³ hybridised C (109.5°), no delocalised electrons (insulator), hardest natural substance, high thermal conductivity. 2) Graphite: giant covalent layered structure, sp² hybridised C (120° hexagonal rings) with London forces between layers (soft lubricant) and 1 delocalised p-electron per C (electrical conductor along layers). 3) Graphene: single 2D atomic layer of sp² hexagons (flexible, transparent, highest electrical/thermal conductivity). 4) C60 Fullerene: simple molecular substance (truncated icosahedron cage of 20 hexagons + 12 pentagons, sp² C, dissolves in non-polar solvents, semiconductor). |
| **Explain the Bonding Triangle (van Arkel–Ketelaar diagram) in IB Chemistry 2023+ syllabus (Structure 2.4).** | The Bonding Triangle plots Average Electronegativity (∑χ / 2) on the horizontal x-axis against Electronegativity Difference (Δχ) on the vertical y-axis to show that ionic, covalent, and metallic bonding form a continuous spectrum rather than rigid categories: Bottom-left (low ∑χ, low Δχ) = Metallic; Bottom-right (high ∑χ, low Δχ) = Covalent (non-polar → polar as Δχ rises); Top apex (large Δχ > 1.8) = Ionic. Allows prediction of intermediate properties (e.g., AlCl3, SiO2, metalloids, alloys). |
| **Summarize the Characteristic Properties of First-Row Transition Elements (Sc to Cu, excluding Zn) and explain paramagnetism vs diamagnetism (HL Structure 3.2).** | Transition elements have an incomplete d-subshell in at least one stable oxidation state (so Zn is not a transition metal). Five characteristic properties: 1) Variable oxidation states (because 4s and 3d energy levels are very close in energy; all show +2 state); 2) Formation of complex ions with monodentate/polydentate ligands via coordinate bonds; 3) Coloured compounds (d–d orbital splitting); 4) Catalytic activity (heterogeneous: Fe in Haber, V2O5 in Contact, Ni in hydrogenation; homogeneous: Fe²⁺ in heme); 5) Magnetic properties: Paramagnetic = contains unpaired d-electrons (attracted into magnetic field); Diamagnetic = all electrons spin-paired (weakly repelled). |
| **In HL Transition Metal Chemistry, list the Spectrochemical Series of ligands and state the 3 factors that determine the magnitude of d-orbital splitting (ΔE) and colour.** | When ligands approach a central metal ion, the 5 degenerate d-orbitals split into lower and higher energy sets; absorbed light promotes an electron across the gap ΔE = hf = hc/λ, and the complementary colour (from the IB Data Booklet colour wheel) is observed. Three factors affect ΔE: 1) Identity and oxidation state of the central metal ion (higher charge = larger ΔE); 2) Geometry of the complex (octahedral vs tetrahedral); 3) Position of the ligand in the Spectrochemical Series: I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < H2O < NH3 < CO ≈ CN⁻ (strong-field ligands cause larger ΔE → absorb shorter λ / higher frequency light). |
| **In IB Energetics (Reactivity 1.1), how do you calculate ΔH from calorimetry (q = mcΔT), why are experimental combustion values less exothermic than Data Booklet values, and how do you extrapolate cooling curves?** | Heat energy transferred to/from water: q = mcΔT (m = mass of water/solution in g, c = 4.18 J g⁻¹ K⁻¹), and ΔH = −q / (1000 × n_limiting) in kJ mol⁻¹. Experimental ΔcH° values using a spirit burner and copper calorimeter are much less exothermic than Data Booklet values due to: 1) Heat loss to surroundings and apparatus; 2) Incomplete combustion (forming soot C and CO); 3) Non-standard conditions and evaporation of volatile fuel. In solution calorimetry, extrapolate the linear cooling curve back to the time of mixing to correct for heat loss. |

| # | Front (Active Recall Prompt) | Back (Verified Exam Explanation) |
| :--- | :--- | :--- |
| **1** | Explain how the Hydrogen Atomic Emission Spectrum provides evidence for quantized Bohr electron energy levels and how to find First Ionisation Energy from convergence (Structure 1.3). | When excited electrons fall from higher energy levels (n) to lower energy levels, they emit photons of discrete frequencies (ΔE = hf = hc/λ), producing a line emission spectrum rather than a continuous spectrum (transitions to n=1 give the UV Lyman series; to n=2 give the visible Balmer series; to n=3 give the IR Paschen series). The spectral lines converge at high frequency because energy levels get closer together at higher n; the convergence limit (n = ∞, where the electron leaves the atom) gives the First Ionisation Energy: IE₁ = L × h × f_limit. |
| **2** | State the rules for drawing orbital box diagrams (Aufbau Principle, Hund's Rule, Pauli Exclusion Principle) and define the maximum electron capacity of main energy level n. | 1) Aufbau Principle: electrons fill lowest-energy subshells first (1s → 2s → 2p → 3s → 3p → 4s → 3d → 4p; note Cr = [Ar] 3d⁵ 4s¹ and Cu = [Ar] 3d¹⁰ 4s¹). 2) Hund's Rule: degenerate orbitals of equal energy are occupied singly with parallel spins before pairing up. 3) Pauli Exclusion Principle: an orbital can hold at most 2 electrons, and they must have opposite spins (+½ and −½). Main shell n holds at most 2n² electrons and n² orbitals. |
| **3** | State the Ideal Gas Equation in IB Chemistry Data Booklet units and specify the two conditions under which real gases deviate most from ideal behaviour (Structure 1.5). | PV = nRT, where P is in kPa (or Pa), V is in dm³ (when P is in kPa) or m³ (when P is in Pa), R = 8.31 J K⁻¹ mol⁻¹, T is in K, and Molar Volume of an ideal gas at STP (273.15 K, 100 kPa) = 22.7 dm³ mol⁻¹. Real gases deviate most from ideal gas assumptions at LOW temperature (intermolecular forces become significant as kinetic energy drops) and HIGH pressure (the finite volume of the gas particles themselves is no longer negligible compared to container volume). |
| **4** | Explain the Periodic Trends across Period 3 and down a Group for Atomic Radius, Ionic Radius, First Ionisation Energy, Electron Affinity, and Electronegativity (Structure 3.1). | Across a Period (left → right): nuclear charge (protons) increases while electrons are added to the same outer shell (similar shielding), increasing effective nuclear charge (Z_eff) → Atomic radius DECREASES, IE₁ INCREASES (with dips at Group 13 p-subshell and Group 16 paired p-orbital), and Electronegativity INCREASES. Down a Group: number of occupied electron shells and shielding increase → Atomic radius INCREASES, IE₁ DECREASES, and Electronegativity DECREASES. Cations are smaller than parent atoms; isoelectronic anions (N³⁻ > O²⁻ > F⁻ > Na⁺ > Mg²⁺ > Al³⁺) shrink as proton number rises. |
| **5** | Using VSEPR Theory, state the Electron Domain Geometry, Molecular Geometry, and Bond Angles for 2, 3, and 4 electron domains (SL & HL Structure 2.2). | Count total Electron Domains (single, double, or triple bond = 1 domain; each lone pair = 1 domain): 1) 2 domains: Linear (180°, e.g., CO2, HCN, BeCl2). 2) 3 domains (Trigonal Planar 120° domain geometry): 3 bp + 0 lp = Trigonal planar (120°, BF3, CO3²⁻); 2 bp + 1 lp = Bent / V-shaped (~117°, SO2, O3, NO2⁻). 3) 4 domains (Tetrahedral 109.5° domain geometry): 4 bp + 0 lp = Tetrahedral (109.5°, CH4, NH4⁺); 3 bp + 1 lp = Trigonal pyramidal (107°, NH3, H3O⁺); 2 bp + 2 lp = Bent / V-shaped (104.5°, H2O). |
| **6** | For HL Chemistry, state the VSEPR Electron Domain and Molecular Geometries for 5 and 6 electron domains. | 5 Electron Domains (Trigonal Bipyramidal domain geometry, 90° axial & 120° equatorial; lone pairs ALWAYS occupy equatorial positions to minimise 90° repulsions): 5 bp + 0 lp = Trigonal bipyramidal (PCl5); 4 bp + 1 lp = Seesaw (SF4); 3 bp + 2 lp = T-shaped (ClF3); 2 bp + 3 lp = Linear (180°, XeF2, I3⁻). 6 Electron Domains (Octahedral 90° domain geometry): 6 bp + 0 lp = Octahedral (SF6); 5 bp + 1 lp = Square pyramidal (BrF5); 4 bp + 2 lp = Square planar (90°, XeF4). |

### Module 3 (INTERMEDIATE): [IB Biology & Chemistry HL: Human Physiology, Neurobiology, Chemical Kinetics, Acids/Bases, Redox & Organic Pathways](/flashcards/sets/13b688fc-4d5c-4811-ac07-2f6706cb6583/)

**Module Scope & Exam Blueprint**: Higher Level (HL) IBDP Biology and Chemistry integration: nephron osmoregulation, sarcomere contraction, antibody/vaccine immunity, menstrual/fertilisation hormones, SN1 vs SN2 stereochemistry, Lewis acids/bases, pKa/pKb buffers, Voltaic/Electrolytic cells, and HL Organic Synthesis.

- **Direct Deck Link**: [IB Biology & Chemistry HL: Human Physiology, Neurobiology, Chemical Kinetics, Acids/Bases, Redox & Organic Pathways (32 Cards)](https://flashcards.world/flashcards/sets/13b688fc-4d5c-4811-ac07-2f6706cb6583/)
- **Browse Level Sets**: [INTERMEDIATE Flashcard Sets on Flashcards.world](https://flashcards.world/flashcards/?q=IB%20Diploma%20Programme%20%28IBDP%20HL%20%26%20SL%29%3A%20Biology%2C%20Chemistry%2C%20Physics%2C%20Economics%2C%20Business%20%26%20TOK&back_lng=en&expertise_level=intermediate)

| High-Yield Exam Concept / Question | Verified Answer & Core Rule |
| :--- | :--- |
| **How do you apply Faraday's Laws of Electrolysis (Q = It = n(e⁻)F) to calculate the mass of metal electroplated at a cathode (HL)?** | 1) Calculate total charge passed in Coulombs: Q = I × t (Current in Amps × Time in seconds); 2) Convert charge into moles of electrons using Faraday's constant (F = 96,500 C mol⁻¹): n(e⁻) = Q / F = (It) / 96500; 3) Use the cathode half-equation stoichiometry (M^(z+) + z e⁻ → M(s)) to find moles of metal deposited: n(M) = n(e⁻) / z. Thus Mass of metal plated = (I × t × Ar) ÷ (z × 96500). |
| **In HL Electrochemistry, state the 3 factors that determine which ions are selectively discharged during the electrolysis of aqueous solutions (e.g., dilute vs concentrated NaCl(aq) and CuSO4(aq) with Cu vs Pt electrodes).** | Selective discharge depends on: 1) Relative Standard Electrode Potentials (E°: at the cathode, the species with the MORE POSITIVE E° is reduced preferentially; at the anode, the species with the MORE NEGATIVE E° is oxidised); 2) Concentration effect (in concentrated NaCl brine, Cl⁻ is oxidised to Cl2 gas at the anode instead of H2O → O2 due to overpotential and high [Cl⁻]); 3) Nature of the electrodes (in CuSO4(aq) with inert Pt/C electrodes, H2O is oxidised at the anode to O2 + 4H⁺; with active copper electrodes, the copper anode itself oxidises: Cu(s) → Cu²⁺(aq) + 2e⁻, used in electrorefining copper). |
| **Compare LithiumAlH4 (LiAlH4) and NaBH4 as reducing agents in HL Organic Chemistry.** | Sodium borohydride (NaBH4, in aqueous/methanolic solution with heat) is a milder, safer reducing agent that reduces Aldehydes (to primary alcohols) and Ketones (to secondary alcohols), but CANNOT reduce carboxylic acids. Lithium aluminium hydride (LiAlH4, in anhydrous ethoxyethane / dry ether followed by dilute acid H⁺ workup, because it reacts violently with water) is a much stronger reducing agent that reduces Carboxylic Acids all the way to Primary Alcohols (as well as aldehydes and ketones). |
| **Outline the 3-step Retro-Synthetic Pathway in HL Organic Chemistry to convert Ethene into Propanoic Acid.** | Since ethene has 2 carbons (C2H4) and propanoic acid has 3 carbons (CH3CH2COOH), the chain must be extended via nucleophilic substitution with cyanide: Step 1: Ethene + HBr → Bromoethane (electrophilic addition at room temperature). Step 2: Bromoethane + KCN in warm aqueous ethanol under reflux → Propanenitrile (CH3CH2CN) + KBr (SN2 nucleophilic substitution). Step 3: Propanenitrile + dilute HCl/H2SO4 heated under reflux → Propanoic acid (CH3CH2COOH) + NH4⁺. |
| **In IB Biology Human Physiology (B3.2 / C3.2), compare the structure and function of Phagocytes, B-Lymphocytes, Helper T-Cells, and Memory Cells, and explain how Monoclonal Antibodies are produced via hybridomas.** | Phagocytes provide non-specific innate immunity via endocytosis and antigen presentation on MHC-II. Helper T-cells bind antigen-MHC, releasing cytokines to activate B-cells whose surface antibodies match the antigen (clonal selection). Activated B-cells divide by mitosis into antibody-secreting Plasma cells and long-lived Memory cells (secondary immunity). Monoclonal antibodies: inject a mouse with target antigen → isolate spleen B-lymphocytes producing the specific antibody → fuse them with endlessly dividing myeloma (cancer) cells to form hybridoma cells → screen via ELISA and culture in fermenters (used in hCG pregnancy tests and targeted cancer therapy). |
| **Explain the cascade of Blood Clotting (Hemostasis) and why coronary thrombosis causes Myocardial Infarction.** | When a blood vessel is damaged, exposed collagen fibres cause platelets to adhere and release clotting factors. Clotting factors trigger a cascade that converts the inactive zymogen prothrombin into the active enzyme thrombin; thrombin then catalyses the conversion of soluble plasma protein fibrinogen into insoluble fibrous strands of fibrin, which form a mesh trapping red blood cells to form a clot. If an atherosclerotic plaque ruptures inside a coronary artery, a thrombus (clot) occludes blood flow, depriving cardiac muscle of O2 and ATP (myocardial infarction). |
| **Contrast Antibiotics (e.g., Penicillin discovered by Florey & Chain) with Antivirals, and explain how HIV destroys the immune system.** | Antibiotics block prokaryotic metabolic pathways (e.g., penicillin inhibits transpeptidase enzymes that cross-link peptidoglycan bacterial cell walls, causing osmotic lysis; others target 70S ribosomes) without harming eukaryotic cells. Viruses lack their own metabolism or cell walls and replicate inside host cells, so antibiotics are completely ineffective against viruses. HIV (a retrovirus using reverse transcriptase) specifically infects and lyses CD4⁺ Helper T-lymphocytes, eventually preventing B-cell activation and antibody production (AIDS). |
| **In HL Biology Kidney Osmoregulation (B3.3 / D3.3), compare the composition of blood in the Renal Artery vs Renal Vein and glomerular filtrate vs urine.** | Renal vein vs Renal artery: Renal vein has much lower urea concentration, lower O2 and higher CO2 (kidney cells respire actively to make ATP for Na⁺ pumps), slightly lower glucose, and regulated optimal ion/water concentrations. Proteins and blood cells are present in blood but ABSENT in both glomerular filtrate and urine (stopped by the basement membrane). Glucose is present in glomerular filtrate at the same concentration as plasma, but 100% reabsorbed in the Proximal Convoluted Tubule (absent in healthy urine). |

| # | Front (Active Recall Prompt) | Back (Verified Exam Explanation) |
| :--- | :--- | :--- |
| **1** | Compare SN1 and SN2 Nucleophilic Substitution mechanisms of halogenoalkanes in IB HL Chemistry (Reactivity 3.4). | SN2 (Bimolecular, favoured by PRIMARY halogenoalkanes and polar aprotic solvents like propanone/DMSO): concerted 1-step mechanism with rate = k[RX][Nu⁻]; nucleophile attacks from the opposite side (backside attack) through a trigonal bipyramidal pentavalent transition state, causing WALDEN INVERSION of stereochemical configuration. SN1 (Unimolecular, favoured by TERTIARY halogenoalkanes and polar protic solvents like water/ethanol): 2-step mechanism with rate = k[RX]; rate-determining heterolytic C–X fission forms a trigonal planar carbocation intermediate, attacked from either side to form a RACEMIC mixture. |
| **2** | Explain why Tertiary Carbocations are more stable than Secondary and Primary Carbocations in both SN1 and Markovnikov Electrophilic Addition. | Carbocation stability follows the order: Tertiary (R3C⁺) > Secondary (R2CH⁺) > Primary (RCH2⁺) > Methyl (CH3⁺). Alkyl groups (–R) have a positive inductive effect (+I) and hyperconjugation, donating electron density towards the positively charged carbon atom. Three electron-releasing alkyl groups delocalise and spread out the positive charge much more effectively than one, lowering the activation energy for forming the tertiary carbocation intermediate. |
| **3** | Compare Brønsted–Lowry, Lewis, and Arrhenius definitions of acids and bases, and explain why transition metal hexaaqua complex ions act as Lewis acid–base adducts (HL Reactivity 3.1 / 3.4). | Brønsted–Lowry: Acid = proton (H⁺) donor; Base = proton (H⁺) acceptor. Lewis: Acid = electron pair ACCEPTOR (electrophile with an empty orbital); Base = electron pair DONOR (nucleophile with a lone pair). Every Brønsted–Lowry base is also a Lewis base, but Lewis acids include species without H⁺ (e.g., BF3, AlCl3, and transition metal cations like Cu²⁺ or Fe³⁺). When [Fe(H2O)6]³⁺ forms, H2O ligands act as Lewis bases donating lone pairs into empty d/s/p orbitals of the Fe³⁺ Lewis acid. |
| **4** | State the HL Acid–Base equations connecting Ka, Kb, Kw, pKa, pKb, pKw, and the Henderson–Hasselbalch Buffer equation. | For any conjugate acid–base pair: Ka × Kb = Kw (1.0 × 10⁻¹⁴ at 298 K), and pKa + pKb = pKw = 14.00 (at 298 K), where pH + pOH = pKw. Henderson–Hasselbalch equation for an acidic buffer: pH = pKa + log₁₀([Conjugate Base A⁻] / [Weak Acid HA]); for a basic buffer: pOH = pKb + log₁₀([BH⁺] / [B]). At the half-equivalence point of a weak acid–strong base titration (where [HA] = [A⁻]), pH = pKa (region of maximum buffering capacity). |
| **5** | Explain why aqueous solutions of NaCl, NH4Cl, CH3COONa, and [Fe(H2O)6]Cl3 are neutral, acidic, or basic (Salt Hydrolysis in HL Chemistry). | 1) Strong acid + Strong base salt (NaCl): neither Na⁺ nor Cl⁻ hydrolyses water → neutral (pH = 7). 2) Strong acid + Weak base salt (NH4Cl): NH4⁺ is the conjugate acid of weak base NH3 and donates H⁺ to water (NH4⁺ + H2O ⇌ NH3 + H3O⁺) → acidic (pH < 7). 3) Weak acid + Strong base salt (CH3COONa): CH3COO⁻ is the conjugate base of weak acid CH3COOH and accepts H⁺ from water (CH3COO⁻ + H2O ⇌ CH3COOH + OH⁻) → basic (pH > 7). 4) Small, high-charge cations like Fe³⁺ or Al³⁺ polarise O–H bonds in coordinated H2O ligands, releasing H⁺ → strongly acidic (pH ~2–3). |
| **6** | Compare Voltaic (Galvanic) Cells and Electrolytic Cells in terms of spontaneity (ΔG°), anode/cathode signs, and electron/ion flow (Reactivity 3.2). | In BOTH cells, Oxidation ALWAYS occurs at the Anode and Reduction ALWAYS occurs at the Cathode ('AN OIL RIG CAT'), and electrons flow through the external wire from Anode to Cathode. 1) Voltaic cell: spontaneous exothermic redox reaction converts chemical energy to electrical energy (E°cell > 0, ΔG° = −nFE°cell < 0); Anode is NEGATIVE and Cathode is POSITIVE; salt bridge (KNO3/KCl) completes circuit by migrating anions to anode and cations to cathode. 2) Electrolytic cell: external DC power supply drives a non-spontaneous reaction (ΔG° > 0); Anode is POSITIVE and Cathode is NEGATIVE. |

### Module 4 (INTERMEDIATE): [IB Physics HL/SL: Space, Time & Motion, Particulate Nature of Matter, Wave Behaviour, Fields & Nuclear/Quantum Physics](/flashcards/sets/19d8f607-55a8-4745-aedb-07a1fe674596/)

**Module Scope & Exam Blueprint**: Complete IBDP Physics (Themes A–E, 2023+ syllabus) revision: kinematics, work/power, rigid body rotational mechanics, special relativity, thermal/greenhouse physics, SHM & wave phenomena, Doppler effect, gravitational/electric/magnetic fields, and quantum/nuclear physics.

- **Direct Deck Link**: [IB Physics HL/SL: Space, Time & Motion, Particulate Nature of Matter, Wave Behaviour, Fields & Nuclear/Quantum Physics (32 Cards)](https://flashcards.world/flashcards/sets/19d8f607-55a8-4745-aedb-07a1fe674596/)
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| High-Yield Exam Concept / Question | Verified Answer & Core Rule |
| :--- | :--- |
| **How do you read a Minkowski Spacetime Diagram (ct vs x) and use the Spacetime Interval Invariant in HL Special Relativity (A.5)?** | On a spacetime diagram (vertical axis = ct, horizontal axis = x): light worldlines always have gradient ±1 (angle 45°), and the worldline of an object moving at speed v has gradient = c / v = 1 / tan θ (where tan θ = v / c; the moving frame's x' and ct' axes scissor symmetrically towards the 45° light line by angle θ). Between any two events, the Spacetime Interval is invariant across all inertial frames: (Δs)² = (cΔt)² − (Δx)² = (cΔt')² − (Δx')². |
| **State the Stefan–Boltzmann Law, Wien's Displacement Law, Albedo, and the Solar Constant in IB Thermal & Greenhouse Physics (B.1 & B.2).** | Black-body radiation power: L = σAT⁴ (Stefan–Boltzmann constant σ = 5.67 × 10⁻⁸ W m⁻² K⁻⁴). Wien's Displacement Law: λ_max T = 2.9 × 10⁻³ m K (hotter stars peak at shorter, bluer wavelengths). Apparent brightness / Intensity at distance d: b = L / (4πd²) (at Earth's orbit, Solar Constant S ≈ 1360 W m⁻²; average incident intensity across Earth's spherical surface is S/4 ≈ 340 W m⁻²). Albedo α = Total scattered/reflected power ÷ Total incident power; Emissivity e = Power radiated by surface ÷ Power radiated by a black body of same A and T. |
| **State the First and Second Laws of Thermodynamics and the equations for Isothermal, Isobaric, Isochoric, and Adiabatic gas processes and Carnot Efficiency (HL B.4).** | Internal energy of an ideal monatomic gas: U = (3/2)nRT = (3/2)Nk_B T. First Law of Thermodynamics: Q = ΔU + W, where work done BY the gas is W = PΔV (area under a P–V diagram). 1) Isochoric (constant V): W = 0, so Q = ΔU. 2) Isobaric (constant P): W = PΔV. 3) Isothermal (constant T): ΔU = 0, so Q = W. 4) Adiabatic (no heat exchange, rapid/insulated): Q = 0, so ΔU = −W and PV^(5/3) = constant (steeper than isothermals on P–V graph). Entropy change: ΔS = ΔQ / T and S = k_B ln Ω. Maximum Carnot heat engine efficiency: η_Carnot = 1 − (T_cold / T_hot). |
| **State the equations for DC Circuits: Kirchhoff's Laws, Potential Divider, and Electric Cells with Internal Resistance (B.5).** | Kirchhoff's First Law (conservation of charge at a junction): ΣI_in = ΣI_out. Kirchhoff's Second Law (conservation of energy around any closed loop): ΣV = 0 (sum of EMFs = sum of IR drops). Terminal voltage of a cell with EMF ε and internal resistance r: V = ε − Ir. Potential divider with resistors R₁ and R₂ in series across V_in: V_out (across R₂) = V_in × [R₂ / (R₁ + R₂)]. |
| **In IB Wave Behaviour (Theme C), state the equations for Simple Harmonic Motion (SHM) displacement, velocity, acceleration, and kinetic/potential energy (SL & HL C.1).** | Defining SHM equation: a = −ω²x, where angular frequency ω = 2π / T = 2πf. For x = x₀ sin(ωt + φ): Velocity v = ωx₀ cos(ωt + φ) = ±ω√(x₀² − x²). Total Mechanical Energy in SHM (constant with no damping): E_total = ½mω²x₀². Potential Energy at displacement x: Ep = ½mω²x² (parabola); Kinetic Energy: Ek = ½mω²(x₀² − x²). Under light damping, amplitude decays exponentially while period remains nearly constant; in forced oscillations, resonance occurs when driving frequency equals natural frequency (f_d = f₀). |
| **Compare Standing Waves in strings fixed at both ends, open pipes (open at both ends), and closed pipes (closed at one end, open at the other) (C.4).** | Displacement Nodes (N) occur at fixed ends/closed pipe ends; Antinodes (A) occur at open pipe ends. 1) String fixed at both ends OR Pipe open at both ends: ALL integer harmonics are present (n = 1, 2, 3, ...), with λ_n = 2L / n and f_n = n × (v / 2L). 2) Pipe closed at one end and open at the other: ONLY ODD harmonics are present (n = 1, 3, 5, ...), with λ_n = 4L / n and f_n = n × (v / 4L) (fundamental L = ¼λ₁). |
| **State the Single-Slit Diffraction equation (θ = λ / b), Rayleigh Criterion for Resolution, and Multiple-Slit / Diffraction Grating effects (HL C.3).** | Single-slit diffraction: angular half-width of the central bright maximum (from centre to first minimum) is θ = λ / b (in radians, where b is slit width). When a double-slit pattern is modulated by single-slit diffraction, bright fringes of spacing s = λD / d lie inside the single-slit envelope. Increasing the number of slits N (towards a diffraction grating, d sin θ = nλ) makes the primary maxima much SHARPER (narrower) and much MORE INTENSE (I ∝ N²), while secondary maxima become negligible. |
| **State the Doppler Effect equations for Sound (moving source vs moving observer) and Electromagnetic Waves (SL & HL C.5).** | For Electromagnetic waves (when Δv ≪ c): Δf / f = Δλ / λ ≈ v / c. For Sound waves (speed v in air, HL): 1) Moving source (speed u_s): f' = f [ v / (v ∓ u_s) ] (use MINUS for source moving TOWARDS observer so frequency increases, PLUS for moving away); 2) Moving observer (speed u_o): f' = f [ (v ± u_o) / v ] (use PLUS for observer moving TOWARDS source, MINUS for moving away). |

| # | Front (Active Recall Prompt) | Back (Verified Exam Explanation) |
| :--- | :--- | :--- |
| **1** | How do you propagate fractional/percentage uncertainties for powers and products in IB Physics Topic A (Data Booklet rules)? | If y = a ± b, absolute uncertainties add: Δy = Δa + Δb. If y = (a × b) / c, fractional uncertainties add: Δy / y = Δa / a + Δb / b + Δc / c. If y = a^n, fractional uncertainty is multiplied by \|n\|: Δy / y = \|n\| (Δa / a) (e.g., for period squared T², % uncertainty = 2 × %ΔT; for √L, % uncertainty = ½ × %ΔL). |
| **2** | State the four SUVAT equations and explain how air resistance (fluid drag) alters the trajectory of a projectile (IB Physics A.1). | SUVAT (constant acceleration only): 1) v = u + at; 2) s = ut + ½at²; 3) v² = u² + 2as; 4) s = ½(u + v)t. With air resistance (acting opposite to instantaneous velocity v): 1) Maximum height is LOWER; 2) Horizontal range is SHORTER; 3) Peak of trajectory is reached earlier in horizontal distance, and the descent path is steeper than the ascent (asymmetric trajectory). |
| **3** | Define Linear Impulse (J = FΔt = Δp) and distinguish between Elastic, Inelastic, and Totally Inelastic Collisions (IB Physics A.2). | Impulse J = F_net Δt = Δp (equal to the area under a Force–Time graph). In ALL isolated collisions (zero external resultant force), Total Linear Momentum is conserved (Σp_before = Σp_after). In an Elastic collision, Total Kinetic Energy is ALSO conserved (and relative speed of approach equals relative speed of separation). In an Inelastic collision, some kinetic energy is converted to thermal/sound/deformation energy (maximum Ek loss occurs when objects stick together in a totally inelastic collision). |
| **4** | State the IB Physics equations for Work Done (W), Elastic Potential Energy, Power (P = Fv), and Efficiency (A.3). | Work done by a constant force at angle θ to displacement: W = Fs cos θ. Elastic potential energy stored in a spring of constant k: E_H = ½k(Δx)². Mechanical power output of a force moving an object at constant velocity v: P = ΔW / Δt = Fv. Efficiency: η = E_useful / E_total = P_useful / P_total. |
| **5** | State the HL Rotational Mechanics equations for Torque (τ), Moment of Inertia (I), Angular Momentum (L), and Rotational Kinetic Energy (A.4). | Rotational equivalents of linear mechanics: Angular kinematics: ω_f = ω_i + αt; θ = ω_i t + ½αt²; ω_f² = ω_i² + 2αθ (with v = ωr and a_t = αr). Torque: τ = Fr sin θ = Iα. Moment of Inertia: I = Σmr² (resistance to angular acceleration). Angular Momentum: L = Iω (conserved when net external torque τ_ext = 0, e.g., ice skater pulling arms in decreases I so ω increases, and ΔL = τΔt). Rotational Kinetic Energy: Ek_rot = ½Iω² = L² / (2I) (a rolling sphere/cylinder has total Ek = ½mv² + ½Iω²). |
| **6** | State the two Postulates of Einstein's Special Relativity and the equations for Time Dilation and Length Contraction using the Lorentz Factor γ (HL A.5). | Postulates: 1) The laws of physics are identical in all inertial (non-accelerating) reference frames; 2) The speed of light in a vacuum (c = 3.00 × 10⁸ m s⁻¹) is constant for all inertial observers regardless of the motion of the source or observer. Lorentz factor: γ = 1 / √(1 − v²/c²) (always ≥ 1). Time Dilation: Δt = γ Δt₀ (where proper time Δt₀ is measured in the frame where the two events occur at the same spatial point—moving clocks run slow). Length Contraction: L = L₀ / γ (where proper length L₀ is measured at rest relative to the object—contracted only parallel to motion). Muon decay at Earth's surface confirms both. |

### Module 5 (ADVANCED): [IB Economics & Business Management HL/SL: Elasticities, Market Failure, Macroeconomics, International Trade & Financial Ratios](/flashcards/sets/b8ab1326-d713-43b5-a72e-e8b1bf5a3d4a/)

**Module Scope & Exam Blueprint**: IBDP Economics (SL & HL Paper 1/2/3) and Business Management (SL & HL) mastery: PED/PES/YED calculations, Pigouvian tax/subsidy welfare triangles, HL Theory of the Firm, Keynesian/Monetarist Macro, Exchange Rates, Ansoff/BCG Matrices, and Financial Ratio Analysis.

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| High-Yield Exam Concept / Question | Verified Answer & Core Rule |
| :--- | :--- |
| **Compare the Monetarist / New Classical (SRAS/LRAS) model and the Keynesian (three-section AS) model of Aggregate Supply.** | Monetarist / New Classical model: SRAS slopes upwards, while LRAS is vertical at full employment output Y_p (Natural Rate of Unemployment); an inflationary gap (Y > Y_p) or recessionary gap (Y < Y_p) self-corrects in the long run via flexible wages shifting SRAS until output returns to Y_p (so demand-side policies only cause inflation in LR). Keynesian AS curve has 3 sections: 1) Horizontal (deep recession, spare capacity—AD increases output with zero inflation); 2) Upward-sloping (approaching capacity, resource bottlenecks); 3) Vertical at Y_max. Keynesians argue wages are 'sticky downwards', so an economy can remain stuck in a deflationary gap indefinitely without fiscal stimulus. |
| **Distinguish between the four types of Unemployment (Cyclical, Structural, Frictional, Seasonal) and evaluate why a low CPI Inflation rate is targeted over Deflation.** | Unemployment Rate = (Number of unemployed actively seeking work ÷ Total Labour Force) × 100%. Natural Rate of Unemployment (NRU) = Structural (skills/geographical/technological mismatch + labour market rigidities) + Frictional + Seasonal. Cyclical (demand-deficient) unemployment occurs during recessions when AD falls. Deflation (falling general price level) is dangerous because: 1) Consumers defer spending expecting lower future prices (deflationary spiral); 2) Real value of debt rises, increasing bankruptcies; 3) Nominal interest rates hit the zero lower bound. |
| **In IB International Economics (HL), draw/calculate the effects of a Tariff vs an Import Quota vs a Production Subsidy on domestic price, imports, tax revenue, and welfare loss.** | At free-trade world price P_w: domestic supply is Q₁, domestic demand is Q₄, and imports are (Q₄ − Q₁). 1) Tariff (P_w + t): domestic output rises to Q₂, consumption falls to Q₃, imports shrink to (Q₃ − Q₂); government collects tariff revenue c = t × (Q₃ − Q₂), and two deadweight welfare loss triangles form (production inefficiency + consumption loss). 2) Quota of (Q₃ − Q₂): same price rise and two welfare loss triangles, plus quota rent goes to foreign exporters/licence holders. 3) Production Subsidy of $s per unit: domestic price stays at P_w (no consumer loss!), domestic supply shifts right so output rises to Q₂, imports shrink to (Q₄ − Q₂), and there is only ONE deadweight welfare loss triangle (production inefficiency). |
| **Contrast Floating, Fixed, and Managed Float Exchange Rate systems, and explain how the Balance of Payments always balances to zero (Current Account = −(Capital + Financial Account)).** | Floating exchange rate: determined purely by market demand and supply of the currency (driven by trade flows, FDI, relative interest rates/hot money, inflation, speculation). Fixed exchange rate: pegged by the central bank buying/selling foreign exchange reserves and adjusting interest rates (upward change = revaluation, downward = devaluation). In the Balance of Payments, any Current Account deficit (exports < imports + net income/transfers) must be financed by a corresponding Capital + Financial Account surplus (borrowing from abroad, FDI inflows, or selling official reserve assets). |
| **Arrange the 6 stages of Economic Integration in order of increasing integration, and distinguish Trade Creation from Trade Diversion in a Customs Union (HL).** | 1) Preferential Trade Area (PTA); 2) Free Trade Area (FTA, e.g., USMCA—removes internal tariffs but members keep independent external tariffs); 3) Customs Union (removes internal tariffs AND adopts a Common External Tariff); 4) Common Market (adds free movement of labour and capital); 5) Economic and Monetary Union (e.g., Eurozone—shared single currency and central bank, losing independent monetary/exchange rate policy); 6) Complete Economic Integration. Trade Creation: production shifts from a high-cost domestic producer to a lower-cost member partner after joining a customs union (welfare gain). Trade Diversion: production shifts from a low-cost non-member outsider (now facing the Common External Tariff) to a higher-cost member partner (welfare loss). |
| **In IB Business Management (Unit 1), compare Sole Traders, Partnerships, Privately Held Companies (Ltd), Publicly Held Companies (PLC), Social Enterprises, and Cooperatives.** | Sole Traders and Partnerships are unincorporated with UNLIMITED liability (owners are personally liable for business debts). Privately Held (Ltd) and Publicly Held (PLC) Companies are incorporated separate legal entities providing LIMITED liability to shareholders (Ltd restricts share sales to invited investors; PLC floats shares on a stock exchange via an IPO). For-profit Social Enterprises (e.g., microfinance, cooperatives) pursue the Triple Bottom Line (Elkington: People, Planet, Profit—social, environmental, and financial sustainability), whereas Non-profit NGOs reinvest 100% of surplus into social missions. |
| **Explain the Ansoff Matrix (4 growth strategies) and STEEPLE / SWOT analysis in IB Business Management Strategic Planning.** | Ansoff Matrix maps Products (Existing vs New) against Markets (Existing vs New) to assess strategic risk: 1) Market Penetration (Existing product + Existing market: lowest risk, price promos/loyalty); 2) Product Development (New product + Existing market: R&D, brand extension); 3) Market Development (Existing product + New geographic/demographic market: overseas expansion); 4) Diversification (New product + New market: highest risk, related vs unrelated conglomerate diversification). STEEPLE analyses external macro-environmental threats/opportunities: Social, Technological, Economic, Environmental, Political, Legal, and Ethical. |
| **Explain the Boston Consulting Group (BCG) Matrix and how it links to the Product Life Cycle and Cash Flow in IB Business Management.** | The BCG Matrix classifies a firm's product portfolio by Market Growth Rate (high vs low) and Relative Market Share (high vs low): 1) Stars (High growth, High share): generate high revenue but require heavy investment to defend growth; 2) Cash Cows (Low growth, High share: Mature stage): generate large positive net cash flows with low investment needs, used to fund Question Marks/R&D (milk strategy); 3) Question Marks / Problem Children (High growth, Low share: Launch stage): consume heavy cash; need holding/building into Stars or divesting; 4) Dogs (Low growth, Low share: Decline stage): harvest or divest. |

| # | Front (Active Recall Prompt) | Back (Verified Exam Explanation) |
| :--- | :--- | :--- |
| **1** | State the Nine Central Concepts of the IB Economics syllabus and how they frame Paper 1 & Paper 2 evaluation. | The 9 overarching IB Economics concepts are: 1) Scarcity; 2) Choice; 3) Efficiency (allocative vs productive); 4) Equity (normative fairness in distribution, distinct from equality); 5) Economic Well-being (multidimensional quality of life); 6) Sustainability (meeting present needs without compromising future generations' resource base); 7) Change; 8) Interdependence; 9) Intervention (government vs market allocation). |
| **2** | In IB Economics Paper 3 (HL Quantitative), how do you calculate linear Demand and Supply functions (Qd = a − bP and Qs = c + dP) and the effects of a specific indirect tax? | In Qd = a − bP: 'a' is the Q-intercept (quantity demanded at P = 0) and '−b' is ΔQd / ΔP (note: gradient on a standard economics graph with P on vertical axis is −1/b). Set Qd = Qs to solve for equilibrium P* and Q*. When a specific tax of $t per unit is imposed on producers, the new supply function replaces P with (P − t): Qs_tax = c + d(P − t). Set Qd = Qs_tax to find the new consumer price P_c, producer price P_p = P_c − t, new quantity Q_tax, government tax revenue = t × Q_tax, and deadweight welfare loss = ½ × t × (Q* − Q_tax). |
| **3** | Why does the Price Elasticity of Demand (PED) vary along a straight-line downward-sloping demand curve, and how does it relate to Total Revenue (TR) and Marginal Revenue (MR)? | Because PED = (ΔQ / ΔP) × (P / Q), even though the slope (ΔQ / ΔP) is constant along a linear demand curve, the ratio (P / Q) changes continuously: 1) Upper half of demand curve (high P, low Q): \|PED\| > 1 (elastic; MR > 0, so lowering price increases Total Revenue); 2) Exact midpoint: \|PED\| = 1 (unitary elastic; MR = 0, Total Revenue is at its MAXIMUM); 3) Lower half (low P, high Q): \|PED\| < 1 (inelastic; MR < 0, so raising price increases Total Revenue). For primary commodities, PED and PES are both inelastic (< 1), causing severe price volatility. |
| **4** | Compare the four types of Market Failure in IB Microeconomics: Negative/Positive Externalities, Common Pool Resources, Public Goods, and Asymmetric Information / Monopoly Power. | 1) Negative Externalities of Production (MSC > MPC) or Consumption (MSB < MPB): over-allocation of resources (Q_m > Q_opt). 2) Positive Externalities of Production (MSC < MPC) or Consumption (MSB > MPB, merit goods): under-allocation (Q_m < Q_opt). 3) Common Pool Resources (rivalrous but non-excludable, e.g., ocean fish stocks, atmosphere, pasture): leads to the 'Tragedy of the Commons' (over-exploitation and depletion, Unsustainability). 4) Pure Public Goods (non-rivalrous and non-excludable): free-rider problem causes missing market. 5) Asymmetric Information (adverse selection & moral hazard) and Abuse of Monopoly Power (restricting output where MR = MC so P > MC). |
| **5** | In HL Microeconomics (Theory of the Firm), compare the Revenue, Cost, and Profit conditions of Perfect Competition, Monopolistic Competition, Oligopoly, and Monopoly. | Economic Profit = Total Revenue − Total Economic Cost (Explicit + Implicit opportunity costs); thus Normal Profit occurs when Economic Profit = 0 (AR = AC at the MC = MR output). Perfect Competition: price taker (horizontal D = AR = MR = P), earns abnormal profit or loss in SR, but zero barriers to entry drive long-run equilibrium to P = MR = MC = minimum AC (both allocatively and productively efficient). Monopoly / Collusive Oligopoly: high barriers to entry allow abnormal profit (AR > AC at MC = MR) to persist in the long run, with P > MC (allocative inefficiency) and output below minimum AC. |
| **6** | In IB Macroeconomics, state the formulas for Nominal vs Real GDP (using the GDP Deflator), Real GDP per capita at PPP, and the Keynesian Multiplier (HL). | Nominal GDP is measured at current market prices via the Output, Income (W+R+I+P), or Expenditure (C + I + G + (X − M)) approaches. Real GDP = (Nominal GDP ÷ GDP Deflator) × 100. Purchasing Power Parity (PPP) adjusts GNI/GDP per capita for differences in local price levels (cost of an identical basket of goods) across countries. HL Keynesian Multiplier: k = 1 / (1 − MPC) = 1 / (MPS + MPT + MPM), where Final ΔReal GDP = k × Initial ΔInjection (ΔI, ΔG, or ΔX). |

### Module 6 (ADVANCED): [IB Psychology, History & Theory of Knowledge (TOK): Biological/Cognitive/Sociocultural Approaches, Authoritarian States & TOK Exhibition/Essay](/flashcards/sets/7ec3c58b-9f16-49e9-ae0c-68f2e0a14171/)

**Module Scope & Exam Blueprint**: IBDP Psychology (Biological, Cognitive, Sociocultural ERQs/SAQs), IB History Paper 2 (Authoritarian States: Mao, Hitler, Castro & Cold War), and Theory of Knowledge (TOK Exhibition 35 prompts, TOK Essay Areas of Knowledge, and Knowledge Framework).

- **Direct Deck Link**: [IB Psychology, History & Theory of Knowledge (TOK): Biological/Cognitive/Sociocultural Approaches, Authoritarian States & TOK Exhibition/Essay (32 Cards)](https://flashcards.world/flashcards/sets/7ec3c58b-9f16-49e9-ae0c-68f2e0a14171/)
- **Browse Level Sets**: [ADVANCED Flashcard Sets on Flashcards.world](https://flashcards.world/flashcards/?q=IB%20Diploma%20Programme%20%28IBDP%20HL%20%26%20SL%29%3A%20Biology%2C%20Chemistry%2C%20Physics%2C%20Economics%2C%20Business%20%26%20TOK&back_lng=en&expertise_level=advanced)

| High-Yield Exam Concept / Question | Verified Answer & Core Rule |
| :--- | :--- |
| **Compare the Emergence and Consolidation of Power of Adolf Hitler (Nazi Germany, Europe) and Mao Zedong (PRC China, Asia) with historiographical perspectives.** | Emergence: Hitler exploited Weimar structural weaknesses (Article 48, proportional representation), the 1929 Great Depression (6 million unemployed), Nazi propaganda (Goebbels), SA street violence, and conservative elite backstairs intrigue (von Papen/Hindenburg appointing Hitler in Jan 1933—Orthodox 'Intentionalist' Bracher vs 'Structuralist' Kershaw/Mommsen). Mao emerged through protracted rural peasant guerrilla warfare (Jiangxi Soviet, Long March 1934–35, Yan'an Rectification), exploiting KMT corruption/hyperinflation and the Japanese invasion (1937–45). Consolidation: Hitler used the Reichstag Fire Decree, Enabling Act (March 1933), Gleichschaltung, Night of the Long Knives (1934), and Gestapo terror (Gellately: popular denunciations). Mao used Land Reform (killing ~1–2 million landlords), Korean War 'Resist America' rallies, Three- and Five-Anti Campaigns (1951–52), Hundred Flowers (1956)/Anti-Rightist Purge, and the Cultural Revolution (1966–76; Chang & Halliday vs Meisner/Spence). |
| **Compare the Economic and Social Policies (especially toward Women and Youth/Minorities) of Mao Zedong and Adolf Hitler (or Fidel Castro).** | Economic: Hitler's Schacht 'New Plan' (Mefo bills, deficit public works) and Göring's Four-Year Plan (1936 autarky & rearmament) cut unemployment but created a 'plunder economy' (Tooze/Mason). Mao's First Five-Year Plan (1953–57, Soviet heavy industry model) succeeded industrially, whereas the Great Leap Forward (1958–62, People's Communes, backyard steel furnaces, Lysenkoism) caused the Great Famine (30–45 million deaths, Dikötter). Women: Hitler's 'Kinder, Küche, Kirche' (Law for Encouragement of Marriage, Mother's Cross) was reactionary, though war forced female labour mobilization by 1943; Mao's 1950 Marriage Law abolished arranged marriages, concubinage, and foot-binding ('Women hold up half the sky'), though patriarchal rural burdens and commune labour persisted. |
| **In IB History Paper 2 (Topic 12: The Cold War), contrast the Orthodox, Revisionist, and Post-Revisionist historiography of the Origins of the Cold War (1945–1949).** | 1) Orthodox / Traditionalist (Feis, Kennan, Schlesinger): blames Stalin's ideological Marxist-Leninist expansionism and violation of Yalta promises in Poland/Eastern Europe ('salami tactics'), forcing defensive US containment (Truman Doctrine 1947, Marshall Plan, NATO). 2) Revisionist (William Appleman Williams, Gar Alperovitz): blames US 'dollar imperialism', open-door capitalist hegemony, and atomic diplomacy (Hiroshima/Nagasaki) for threatening legitimate Soviet security buffer needs after losing 27 million citizens in WWII. 3) Post-Revisionist (John Lewis Gaddis, early work): synthesises both, arguing mutual misperception, security dilemmas, and power vacuums drove escalation (though Gaddis's post-1991 'New Cold War History' using Soviet archives shifted blame back toward Stalin's authoritarian paranoia). |
| **In IB History Paper 1 (Source-Based Prescribed Subject), state the exact method for Question 2 (OPCVL: Origin, Purpose, Content, Value, and Limitations) and Question 4 (Mini-Essay).** | Question 2 (4 marks—OPCVL of ONE source): Write two distinct paragraphs—Paragraph 1 (Values): state the Origin (author, date, type of source), Purpose (intended audience and why it was created), and Content, explaining specifically how at least two of these give VALUE to a historian studying the topic. Paragraph 2 (Limitations): explain how the Origin, Purpose, and historical context create specific LIMITATIONS (avoid the banned word 'biased' without explaining *why* and *how* the author's position distorts or omits evidence). Question 4 (9 marks): synthesise ALL FOUR sources (Sources I, J, K, L) AND detailed own historical knowledge in thematic paragraphs addressing both sides of the prompt. |
| **What is the structure of Theory of Knowledge (TOK) in the IB Diploma, and how are the TOK Exhibition (1/3) and TOK Essay (2/3) assessed?** | TOK assesses how we know what we claim to know (epistemology) and combines with the Extended Essay (EE) for up to 3 core bonus IB Diploma points. 1) TOK Exhibition (Internal Assessment, 950 words max, 10 marks = 33%): Student selects ONE of the 35 IA prompts, chooses an optional Theme, and curates THREE specific, real-world objects (with personal/historical context, not generic stock images), explaining how each object manifests the prompt in the real world. 2) TOK Essay on a Prescribed Title (External Assessment, 1,600 words max, 10 marks = 67%): Student chooses 1 of 6 prescribed titles and evaluates knowledge claims and counterclaims across two specified Areas of Knowledge (AOKs). |
| **List the Five Areas of Knowledge (AOKs), the Five Optional Themes, and the Four Elements of the Knowledge Framework in the IB TOK syllabus.** | Five Areas of Knowledge (AOKs): 1) History; 2) The Human Sciences; 3) The Natural Sciences; 4) The Arts; 5) Mathematics. Core Theme: Knowledge and the Knower. Five Optional Themes (study 2): Knowledge and Technology; Knowledge and Language; Knowledge and Politics; Knowledge and Religion; Knowledge and Indigenous Societies. Every AOK and Theme is analysed using the Four Elements of the Knowledge Framework: 1) Scope (what counts as knowledge in this AOK and what problems it solves); 2) Perspectives (paradigms, cultural/historical context, knower biases); 3) Methods and Tools (how knowledge is produced and verified); 4) Ethics (moral responsibilities and constraints on knowers). |
| **List the 12 Key TOK Concepts that should be woven into every TOK Exhibition and TOK Essay.** | The 12 official IB TOK Concepts are: 1) Evidence; 2) Certainty; 3) Truth; 4) Interpretation; 5) Power; 6) Justification; 7) Explanation; 8) Objectivity; 9) Perspective; 10) Culture; 11) Values; 12) Responsibility. |
| **Contrast the Methods and Tools of the Natural Sciences vs the Human Sciences in a TOK Essay.** | Natural Sciences (Physics, Chemistry, Biology): study inanimate matter or biological organisms that obey invariant, universal laws; rely on hypothetico-deductive induction, controlled isolation of variables, quantitative measurement, peer review, and Popperian falsifiability (though subject to Kuhn's paradigm shifts and theory-ladenness of observation). Human Sciences (Psychology, Economics, Anthropology): study conscious, self-reflective human agents with free will; face the Hawthorne/Observer Effect, ethical limits on experimentation, reflexive feedback loops (e.g., economic predictions altering market behaviour—Goodhart's Law), and cultural context, requiring both quantitative models and Verstehen (empathetic qualitative interpretation). |

| # | Front (Active Recall Prompt) | Back (Verified Exam Explanation) |
| :--- | :--- | :--- |
| **1** | In IB Psychology Biological Approach (BLOA), name the key studies and mechanisms for Neuroplasticity, Neurotransmission, and Hormones/Pheromones. | 1) Localization & Neuroplasticity: Maguire et al. (2000)—MRI scans of 16 London taxi drivers showed significantly greater grey matter volume in the posterior hippocampus (spatial memory) correlated with years of driving experience (+ Draganski et al. 2004 juggling study). 2) Excitatory/Inhibitory Neurotransmission: Antonova et al. (2011)—scopolamine (acetylcholine antagonist) reduced hippocampal activation during a virtual water-maze spatial memory task; Crockett et al. (2010)—citalopram (SSRI boosting serotonin) increased prosocial behaviour in the Ultimatum Game. 3) Hormones & Pheromones: Newcomer et al. (1999)—high cortisol levels impaired verbal declarative memory; Wedekind (1995)—sweaty T-shirt MHC dissimilarity study (critiqued for lack of conclusive human pheromone evidence). |
| **2** | In IB Psychology Biological Approach, what are the key Twin/Adoption and Molecular Genetics studies for Evolutionary Psychology and Genetic Inheritance? | 1) Twin & Kinship Studies: Bouchard et al. (1990) Minnesota Twin Family Study—monozygotic twins reared apart (MZA) had 0.70 correlation in IQ (vs 0.86 MZT together), showing strong genetic heritability alongside environmental variance; Kendler et al. (2006)—44% MZ vs 16% DZ concordance for Major Depressive Disorder. 2) Molecular Gene × Environment Interaction: Caspi et al. (2003)—Dunedin longitudinal study of 847 New Zealanders found individuals with two short alleles of the 5-HTT serotonin transporter gene developed significantly more depression ONLY after experiencing ≥3 stressful life events (diathesis-stress model). 3) Evolution: Curtis et al. (2004) pathogen disgust evolution. |
| **3** | In IB Psychology Cognitive Approach (CLOA), summarize the core studies for Models of Memory, Schema Theory, Thinking & Decision-Making (Dual Process Model), and Reconstructive/Flashbulb Memory. | 1) Memory Models: Glanzer & Cunitz (1966) serial position curve (primacy + recency supporting MSM) and Landry & Bartling (2011) articulatory suppression supporting WMM. 2) Schema Theory: Brewer & Treyens (1981) office study (30% falsely recalled books in an academic office lacking books due to office schema) and Bartlett (1932) 'War of the Ghosts'. 3) Thinking & Decision-Making (Kahneman & Tversky Dual-Process Theory: System 1 fast/intuitive/heuristic vs System 2 slow/rational): Tversky & Kahneman (1974) Anchoring & Adjustment heuristic (8×7×...×1 vs 1×2×...×8) and Alter et al. (2007) font disfluency activating System 2. 4) Flashbulb Memory: Brown & Kulik (1977) amygdala arousal hypothesis vs Talarico & Rubin (2003) 9/11 study showing FBM accuracy decays just like everyday memory, only vividness/confidence stays high. |
| **4** | In IB Psychology Sociocultural Approach (SCLOA), summarize the core studies for Social Identity Theory (SIT), Social Cognitive Theory (SCT), Stereotypes, and Enculturation/Acculturation. | 1) Social Identity Theory (Tajfel & Turner, 1979: Social Categorisation → Social Identification → Social Comparison / In-group favouritism & Out-group discrimination to boost self-esteem): Tajfel et al. (1970) Klee/Kandinsky minimal group paradigm—boys allocated points to maximise difference in favour of their in-group even over maximum joint profit. 2) Social Cognitive Theory: Bandura et al. (1961) Bobo doll study and Joy, Kimball & Zabrack (1986) Notel natural experiment. 3) Stereotype Formation & Threat: Steele & Aronson (1995)—African American students scored lower on verbal GRE tests only when framed as a diagnostic test of intelligence (stereotype threat). 4) Culture & Acculturation (Berry's 4 strategies: Assimilation, Integration, Separation, Marginalisation): Miranda & Matheny (2000) acculturative stress in Latino immigrants; Berry (1967) Temne vs Inuits conformity. |
| **5** | How do you distinguish between a Short Answer Question (SAQ, 9 marks) and an Extended Response Question (ERQ, 22 marks) in IB Psychology Paper 1? | SAQ (9 marks, ~15–20 mins, command terms: Describe, Explain, Outline): NO critical evaluation required! Structure: 1) Clear definition and explanation of the psychological theory/concept (3 marks); 2) Detailed description of ONE relevant empirical study (Aim, Procedure, Findings, Conclusion) explicitly linked back to how it demonstrates the theory (6 marks). ERQ (22 marks, ~45 mins, command terms: Discuss, Evaluate, To what extent, Contrast): requires a thesis introduction, thorough explanation of the theory, at least TWO detailed empirical studies, and sustained critical evaluation (TEACUP: Testability, Empirical evidence, Applications, Construct validity, Unbiased sample/ethnocentrism, Practical/ethical issues). |
| **6** | In IB History Paper 2 (Topic 10: Authoritarian States), what are the three syllabus pillars for comparing two leaders from different regions (e.g., Hitler in Germany, Mao in China, Castro in Cuba)? | IB History Paper 2 requires cross-regional comparison under three thematic rubrics: 1) Emergence of Authoritarian States: Conditions in which the state emerged (economic crisis, social division, impact of war, weakness of existing political system—Weimar/Batista/KMT) vs Methods used to establish power (persuasion/propaganda, coercion/force, charismatic leadership, ideology). 2) Consolidation and Maintenance of Power: Use of legal methods, force/terror, charismatic leadership, propaganda, nature/extent of opposition, and impact of foreign policy. 3) Aims and Results of Policies: Domestic economic, political, cultural, and social policies, plus impact on women and minorities. |

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## 3. 4-Phase Active Recall & Spaced Repetition Study Plan

| Study Phase | Actionable Protocol |
| :--- | :--- |
| **Phase 1: Foundation & Core Definitions (Days 1–7)** | Complete Modules 1 & 2 (`basic`). Focus on foundational terminology, statutory definitions, core formulas, and classification rules using daily 20-minute active-recall sessions. |
| **Phase 2: Mechanisms, Applied Problem-Solving & Frameworks (Days 8–16)** | Master Modules 3 & 4 (`intermediate`). Practice multi-step mechanisms, comparative tables, case applications, and quantitative shortcuts while reviewing Phase 1 leeches. |
| **Phase 3: Advanced Vignettes, Edge Cases & High-Difficulty Synthesis (Days 17–24)** | Complete Modules 5 & 6 (`advanced`). Drill high-discrimination exam traps, clinical/legal vignettes, and multi-topic synthesis cards under timed conditions. |
| **Phase 4: Spaced-Repetition Consolidation & Pre-Exam Sprint (Final 7 Days)** | Filter ausschließlich for cards marked 'Again' or 'Hard' across all 192 cards, interleave all 6 decks, and simulate timed exam blocks. |

---

## 4. Top 5 High-Yield Exam Strategies & Scoring Tips

- **Exploit the IB Data Booklet in Chemistry and Physics (Paper 1B & Paper 2)**: Never waste memory on constants that are printed in the official IB Physics or IB Chemistry Data Booklet—instead, memorize *which* sub-topic each equation belongs to, the exact SI units required (e.g., `kPa` + `dm³` in IB Chemistry `PV = nRT`), and how to propagate fractional uncertainties (`Δy/y = |n| Δx/x`).
- **Master Paper 1B Data-Based & Experimental Questions in IB Sciences (2023+ Syllabus)**: Under the updated IB Biology, Chemistry, and Physics assessment model, Paper 1B tests experimental design, uncertainty propagation, graph linearization, and evaluating methodology. Always distinguish **random uncertainties** (precision, reduced by repeats) from **systematic errors** (accuracy, caused by experimental design flaws).
- **Use the 'DEADE' Framework for IB Economics Paper 1 & Paper 2 Essays**: Every 10- or 15-mark IB Economics essay should follow **D**efinitions → **E**xplanation of economic theory → **A**pplication to a specific Real-World Example (named country, policy, year, and impact) → **D**iagram (large, fully labelled with arrows and equilibria) → **E**valuation using the 9 Central Concepts and CLASPP.
- **Pair Empirical Studies Strategically in IB Psychology SAQs vs ERQs**: You can cut your IB Psychology study load in half by selecting versatile studies that work across multiple topics (e.g., *Maguire et al. 2000* for Localization, Neuroplasticity, and MRI Brain Imaging; *Caspi et al. 2003* for Genetics, Evolutionary/Depression Etiology, and Correlational Methods).
- **Secure All 3 Core Bonus Points in TOK and the Extended Essay**: Never use generic stock photos in your TOK Exhibition—anchor all 3 objects in specific, personal or historical real-world contexts. In your Extended Essay, devote over 50% of your effort to **Criterion C (Critical Thinking, 12/34 marks)** by continuously evaluating source/method limitations rather than writing a descriptive report.

---

## 5. Frequently Asked Questions (FAQ)

### Are these flashcards aligned with the updated 2023–2026 IB Diploma (IBDP) syllabuses?
Yes. The IB Biology (Themes A–D: Unity & Diversity, Form & Function, Interaction & Interdependence, Continuity & Change), IB Chemistry (Structure 1–3 & Reactivity 1–3), IB Physics (Themes A–E), IB Economics, Business Management, Psychology, History, and Theory of Knowledge decks are fully aligned with the latest IBDP curriculum updates.

### Can both Standard Level (SL) and Higher Level (HL) IB students use these decks?
Yes. Modules 1, 2, 4, 5, and 6 cover the shared SL/HL core concepts alongside clearly marked Higher Level (HL) extensions, while Module 3 focuses specifically on high-yield HL Biology and HL Chemistry mechanisms (SN1/SN2, Lewis acids, pKa buffers, nephron osmoregulation, and reproduction).

### How can I score a 7 in IB Sciences and Individuals & Societies?
Scoring a 7 (typically ~72–78%+ raw mark depending on subject grade boundaries) requires mastering two areas where 5/6-grade students drop marks: exact mark-scheme keywords on Paper 2 short-answer questions, and structured evaluation (AO3) on Paper 1B/2/3 extended responses.

---
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